Bài 1:
a,2^3.3^2-5^16÷5^14 c,4^7.3^4.9^6/6^13
=8.9-5^2=72-25=47 =(2^2)^7.3^4.(3^2)^6/(2.3)^13
b,(-3)^9÷(-3)^7+5.(-2)^2 =2^14.3^4.3^12/2^13.3^13
=(-3)^2+5.4 = 2^14.3^16/2^13.3^13=2.3^3=2.27=54
=9+20=29
Bài 2:
a, (x-1)^2-36=0 b, (2x+1)^3+126=2020^0
(x-1)^2=36 (2x+1)^3+126=1
⇒x-1=6 hoặc x-1=-6 (2x+1)^3 =1-126=-125
1;x-1=6⇒x=1+6=7 ⇒ 2x+1=-5⇒2x=-5-1=-6⇒x=-6÷2=-3
2;x-1=-6 ⇒x=-6+1=-5 Vậy x=-3
Vậy x=7 hoặc x=-5
c,(x+1)^16=(x+1)^13
⇒(x+1)^16-(x+1)^13=0
⇒(x+1)^13.(x+1)^3-(x+1)^13=0
⇒(x+1)^13. [(x+1)^3-1]=0
⇒(x+1)^13=0 hoặc (x+1)^3-1=0
1; (x+1)^13=0
⇒x+1=0⇒x=-1
2, (x+1)^3 -1=0
⇒(x+1)^3=1
⇒x+1=1⇒x=0
Vậy x=-1 hoặc x=0
