5-x/4x-8+7/8x=x-1/2x(x-2)+1/8x-16 ĐKXĐ:x$\neq$ 2
(=)5-x/4x-8 + 7/8x - x-1/2x(x-2)- 1/8x-16=0 x$\neq$0
(=)5-x/4(x-2)+7/8x- x-1/2x(x-2)-1/8(x-2)=0
(=)2x(5-x)+7(x-2)-4(x-1)-x/8x(x-2)=0
(=)10x-2x²+7x-14-4x+4-x=0
(=)-2x²+12x-10=0
(=)-2x²+2x+10x-10=0
(=)-2x(x-1)+10(x-1)=0
(=)(-2x+10)(x-1)=0
(=)\(\left[ \begin{array}{l}-2x+10=0\\x-1=0\end{array} \right.\) (=)\(\left[ \begin{array}{l}-2x=-10\\x=1\end{array} \right.\) (=)\(\left[ \begin{array}{l}x=5\\x=1\end{array} \right.\)
S={5;1}
