`C1:2Al+6HCl->2AlCl_3+3H_2`
`Fe+2HCl->FeCl_2+H_2`
`n_{Al;Fe}=x;y(mol)`
`n_{H_2}=(15,68)/(22,4)=0,7(mol)=3/2x+y`
`m_{hh}=27x+56y=27,8`
$\begin{cases} \dfrac{3}{2}x+y=0,7\\27x+56y=27,8\end{cases}$
$\begin{cases} x=0,2\\y=0,4\end{cases}$
`%m_{Al}=(0,2.27)/(27,8%)=19,42%`
`%m_{Fe}=100%-19,42%=80,58%`
`C2:``Zn+HCl->ZnCl_2+H_2`
`Cu+HCl->X`
`n_{H_2}=(4,48)/(22,4)=0,2(mol)`
`n_{Zn}=n_{H_2}=0,2(mol)`
`%m_{Zn}=(0,2.65)/(20%)=65%`
`%m_{Cu}=100%-65%=35%`
`n_{HCl}=0,2.2=0,4(mol)`
`V_{HCl}=(0,4)/(0,5)=0,8(l)`