Đáp án:
số mol KMnO4 là :n=12.64(39+55+16⋅4)=0.08(mol)n=12.64(39+55+16⋅4)=0.08(mol)
PTHH 2KMnO4→K2MnO4+MnO2+O22KMnO4→K2MnO4+MnO2+O2
3Fe+2O2→Fe3O43Fe+2O2→Fe3O4
mFe3O4=n.M=(nO⋅12).(56⋅3+16⋅4)=[(0,08⋅12)⋅12]⋅(56⋅3+16⋅4)=4.64(g)mFe3O4=n.M=(nO⋅12).(56⋅3+16⋅4)=[(0,08⋅12)⋅12]⋅(56⋅3+16⋅4)=4.64(g)