Giải thích các bước giải:
`a)`
`(x-1/2)^10=0`
`=>x-1/2=0`
`=>x=0+1/2`
`=>x=1/2`
Vậy `x=1/2`
`b)`
`(2x-1)^3=-8`
`=>(2x-1)^3=(-2)^3`
`=>2x-1=-2`
`=>2x=-2+1`
`=>2x=-1`
`=>x=-1/2`
Vậy `x=-1/2`
`c)`
`(x+1/2)^2=1/16`
`=>(x+1/2)^2=(+-1/4)^2`
`=>[(x+1/2=1/4),(x+1/2=-1/4):}`
`=>[(x=1/4-1/2),(x=-1/4-1/2):}`
`=>[(x=1/4-2/4),(x=-1/4-2/4):}`
`=>[(x=-1/4),(x=-3/4):}`
Vậy `x\in{-1/4;-3/4}`