a, x + `1/2` = `1/6`
x = `1/6` - `1/2`
x = `1/6` - `3/6`
x = `-2/6`
x = `-1/3`
Vậy x = `-1/3`
b, `1/4` + `3/4`x = 2
`3/4`x = 2 - `1/4`
`3/4`x = `8/4` - `1/4`
`3/4`x = `7/4`
x = `7/4` : `4/3`
x = `7/4` . `3/4`
x = `21/16`
Vậy x = `21/16`
c, `2/3` + `4/3` : x = 1
`4/3` : x = 1 - `2/3`
`4/3` : x = `1/3`
x = `4/3` : `1/3`
x = `4/3` . 3
x = 4
Vậy x = 4
d, 3`1/4` : 0,5 = 2x : 0,02
`13/4` : `1/2` = 2x : `2/100`
`13/4` . 2 = 2x : `1/50`
`26/4` = 2x . 50
`26/4` : 50 = 2x
`13/2` . `1/50` = 2x
`13/100` = 2x
`=>` x = `13/100` : 2
x = `13/100` . `1/2`
x = `13/200`
Vậy x = `13/200`
e, | x - 1 | - 5 = -2
| x - 1 | = -2 + 5
| x - 1 | = 3
`=>` \(\left[ \begin{array}{l}x-1=3\\x-1=-3\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}x=4\\x=-2\end{array} \right.\)
Vậy x ∈ { -2 ; 4 }
