a) x + $\frac{1}{6}$ = $\frac{-3}{8}$
x = $\frac{-3}{8}$ - $\frac{1}{6}$
x = $\frac{-13}{24}$
Vậy x = $\frac{-13}{24}$
b) $\frac{1}{2}$x + $\frac{1}{8}$x = $\frac{3}{4}$
x ($\frac{1}{2}$ + $\frac{1}{8}$)= $\frac{3}{4}$
x . $\frac{5}{8}$ = $\frac{3}{4}$
x = $\frac{3}{4}$ : $\frac{5}{8}$
x = $\frac{6}{5}$
Vậy x = $\frac{6}{5}$
c) 2 - |$\frac{3}{4}$ - x| = $\frac{7}{12}$
|$\frac{3}{4}$ - x| = 2 - $\frac{7}{12}$
|$\frac{3}{4}$ - x| = $\frac{17}{12}$
TH1: $\frac{3}{4}$ - x = $\frac{17}{12}$
x = $\frac{3}{4}$ - $\frac{17}{12}$
x = $\frac{-2}{3}$
TH2: $\frac{3}{4}$ - x = $\frac{-17}{12}$
x = $\frac{3}{4}$ - $\frac{-17}{12}$
x = $\frac{13}{6}$
Vậy x ∈ {$\frac{-2}{3}$; $\frac{13}{6}$}
d) (2x - 4,5) : $\frac{3}{4}$ - $\frac{1}{3}$ = 1
(2x - 4,5) : $\frac{3}{4}$ = 1 + $\frac{1}{3}$
(2x - 4,5) : $\frac{3}{4}$ = $\frac{4}{3}$
(2x - 4,5) = $\frac{4}{3}$ x $\frac{3}{4}$
2x - 4,5 = 1
2x = 1 + 4,5
2x = $\frac{11}{2}$
x = $\frac{11}{2}$ : 2
x = $\frac{11}{4}$
Vậy x = $\frac{11}{4}$
