Đáp án:
↓↓
Giải thích các bước giải:
`a)`
`2x(x-1)=3x-3`
`⇒2x(x-1)-3x+3=0`
`⇒2x(x-1)-3(x-1)=0`
`⇒(x-1)(2x-3)=0`
`<=>`\(\left[ \begin{array}{l}x-1=0\\2x-3=0\end{array} \right.\) `=>`\(\left[ \begin{array}{l}x=1\\2x=3\end{array} \right.\) `=>` \(\left[ \begin{array}{l}x=1\\x=\frac{3}{2}\end{array} \right.\)
Vậy \(\left[ \begin{array}{l}x=0\\x=\frac{3}{2}\end{array} \right.\)
`b)`
`x^2-6x=0`
`⇒x(x-6)=0`
`<=>` \(\left[ \begin{array}{l}x=0\\x-6=0\end{array} \right.\) `=>`\(\left[ \begin{array}{l}x=0\\x=6\end{array} \right.\)
Vậy \(\left[ \begin{array}{l}x=0\\x=6\end{array} \right.\)
`c)`
`x(x-3)-x^2+3=0`
`⇒x(x-3)-x(x-3)=0`
`⇒(x-3)(x-x)=0`
`⇒(x-3).0=0`
`⇒x-3=0`
`⇒x=3.`
