a) $\frac{-2}{3}$ . x + 1$\frac{2}{5}$ = 0,6
$\frac{-2}{3}$ . x = 0,6 - 1$\frac{2}{5}$
$\frac{-2}{3}$ . x = $\frac{-4}{5}$
x = $\frac{-4}{5}$ : $\frac{-2}{3}$
x = $\frac{-4}{5}$ . $\frac{-3}{2}$
x = $\frac{6}{5}$
Vậy x = x = $\frac{6}{5}$
b) [$\frac{3}{2}$ - 2x] - 1 = 25%
$\frac{3}{2}$ - 2x = 25% + 1
$\frac{3}{2}$ - 2x = $\frac{1}{4}$ + 1
$\frac{3}{2}$ - 2x = $\frac{5}{4}$
2x = $\frac{3}{2}$ - $\frac{5}{4}$
2x = $\frac{1}{4}$
x = $\frac{1}{4}$ : 2
x = $\frac{1}{8}$
Vậy x = $\frac{1}{8}$
c) $\frac{3}{2}$ - 2 . $x^{2}$ = $\frac{-1}{2}$
2 . $x^{2}$ = $\frac{3}{2}$ - $\frac{-1}{2}$
2 . $x^{2}$ = 2
$x^{2}$ = 2 : 2
$x^{2}$ = 1
\(\left[ \begin{array}{l}x=1\\x=-1\end{array} \right.\)
Vậy x = 1 hoặc x = -1
