Giải thích các bước giải:
Ta có:
\(\begin{array}{l}
a,\\
3\left( {{2^2} + 1} \right)\left( {{2^4} + 1} \right)\left( {{2^8} + 1} \right)\left( {{2^{16}} + 1} \right)\\
= \left( {{2^2} - 1} \right)\left( {{2^2} + 1} \right)\left( {{2^4} + 1} \right)\left( {{2^8} + 1} \right)\left( {{2^{16}} + 1} \right)\\
= \left( {{2^4} - 1} \right)\left( {{2^4} + 1} \right)\left( {{2^8} + 1} \right)\left( {{2^{16}} + 1} \right)\\
= \left( {{2^8} - 1} \right)\left( {{2^8} + 1} \right)\left( {{2^{16}} + 1} \right)\\
= \left( {{2^{16}} - 1} \right)\left( {{2^{16}} + 1} \right)\\
= {2^{32}} - 1\\
b,\\
x\left( {2{x^2} - 3} \right) - {x^2}\left( {5x + 1} \right) + {x^2}\\
= 2{x^3} - 3x - 5{x^3} - {x^2} + {x^2}\\
= - 3{x^3} - 3x = - 3x\left( {{x^2} + 1} \right)\\
c,\\
3x\left( {x - 2} \right) - 5x\left( {1 - x} \right) - 8\left( {{x^2} - 3} \right)\\
= 3{x^2} - 6x - 5x + 5{x^2} - 8{x^2} + 24\\
= - 11x + 24
\end{array}\)
