$a) (x-7)(x+12)=0$
\(\left[ \begin{array}{l}x-7=0\\x+12=0\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}x=7\\x=-12\end{array} \right.\)
$d) (2y-16)(8x-24)=0$
\(\left[ \begin{array}{l}2y-16=0\\8x-24=0\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}2y=16\\8x=24\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}y=8\\x=3\end{array} \right.\)
$i) x.y=-5$
⇒ \(\left[ \begin{array}{l}x=1\\y=-5\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=-1\\y=5\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=5\\y=-1\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=-5\\y=1\end{array} \right.\)
$b) (3x-15)(6-2x)=0$
\(\left[ \begin{array}{l}3x-15=0\\6-2x=0\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}3x=15\\2x=6\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}x=5\\x=3\end{array} \right.\)
$e) (22-11y)(20-4x)=0$
\(\left[ \begin{array}{l}22-11y=0\\20-4x=0\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}11y=22\\4x=20\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}y=2\\x=5\end{array} \right.\)
$k) (x+4)(y-5)=-3$
\(\left[ \begin{array}{l}x+4=1\\y-5=-3\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}x=-3\\y=-8\end{array} \right.\)
\(\left[ \begin{array}{l}x+4=-1\\y-5=3\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}x=-5\\y=8\end{array} \right.\)
\(\left[ \begin{array}{l}x+4=3\\y-5=-1\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}x=-1\\y=4\end{array} \right.\)
\(\left[ \begin{array}{l}x+4=-3\\y-5=1\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}x=-7\\y=6\end{array} \right.\)
$p) (x-5)(x+2)=0$
\(\left[ \begin{array}{l}x-5=0\\x+2=0\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}x=5\\y=-2\end{array} \right.\)
$c) (3x+9)(4y-8)=0$
\(\left[ \begin{array}{l}3x+9=0\\4y-8=0\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}3x=-9\\4y=8\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}x=-3\\y=2\end{array} \right.\)
$g) (7y+14)(9x-18)=0$
\(\left[ \begin{array}{l}7y+14=0\\9x-18=0\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}7y=-14\\9x=18\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}y=-2\\x=2\end{array} \right.\)
$m) (x-9)(y-5)=-1$
\(\left[ \begin{array}{l}x-9=1\\y-5=-1\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}x=10\\y=4\end{array} \right.\)
\(\left[ \begin{array}{l}x-9=-1\\y-5=1\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}x=8\\y=6\end{array} \right.\)
$9) (4y-3)(5y+1)=0$
\(\left[ \begin{array}{l}4y-3=0\\5y+1=0\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}4y=3\\5y=-1\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}y=\frac{3}{4}\\y=\frac{-1}{5}\end{array} \right.\)
$h) x.y=3$
⇒ \(\left[ \begin{array}{l}x=1\\y=3\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=-1\\y=-3\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=3\\y=1\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=-3\\y=-1\end{array} \right.\)
$n) (x+3)(x+4=0$
\(\left[ \begin{array}{l}x+3=0\\x+4=0\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}x=-3\\y=-4\end{array} \right.\)