a\(\dfrac{5}{6}x-\dfrac{2}{3}=3\dfrac{1}{2}\)

b\(\dfrac{4}{5}-\dfrac{3}{4}\div x=0,3\)

c\(\dfrac{-3}{2}-\dfrac{1}{4}x=1\dfrac{1}{3}-0,2x\)

d\(\left|\dfrac{3}{5}x+\dfrac{4}{3}\right|:\dfrac{2}{3}-0,5=1\dfrac{1}{2}\)

e\(\dfrac{4x-5}{2-3x}=\dfrac{3}{4}\)

giúp mình nhé

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