Giải thích các bước giải:
`a)`
`x^2=x^5`
`=>x^2-x^5=0`
`=>x^2 .1-x^2 .x^3=0`
`=>x^2 .(1-x^3)=0`
TH`1`:
`x^2=0`
`=>x=0`
TH`2`
`1-x^3=0`
`=>x^3=1-0`
`=>x^3=1`
`=>x=1`
Vậy `x\in{0;1}`
`b)`
`5^x +5^(x+2)=650`
`=>5^x .1+5^x .25=650`
`=>5^x .(1+25)=650`
`=>5^x .26=650`
`=>5^x =650:26`
`=>5^x=25`
`=>5^x=5^2`
`=>x=2`
Vậy `x=2`
`c)`
`32^x .16^x=1024`
`=>(2^5)^x .(2^4)^x=2^10`
`=>2^(5x) .2^(4x)=2^10`
`=>2^(5x+4x)=2^10`
`=>2^(9x)=2^10`
`=>9x=10`
`=>x=10/9`
Vậy `x=10/9`
