Đáp án + giải thích các bước giải:
A/
1) `9x^2-2x+1/9=(3x)^2-2.3.x. 1/3+(1/3)^2=(3x-1/3)^2`
2) `x^4+x^3-8x-8=x^3(x+1)-8(x+1)=(x^3-8)(x+1)=(x-2)(x^2+2x+4)(x+1)`
B/
`x^2(2x-5)+(5-2x)=0`
`->x^2(2x-5)-(2x-5)=0`
`->(x^2-1)(2x-5)=0`
`->(x-1)(x+1)(2x-5)=0`
`->`\(\left[ \begin{array}{l}x-1=0\\x+1=0\\2x-5=0\end{array} \right.\)
`->`\(\left[ \begin{array}{l}x=1\\x=-1\\x=\dfrac{5}{2}\end{array} \right.\)