a)2x²-4x+2= 2x²-2x-2x+2=(2x²-2x)-(2x-2)=2x(x-1)+2(x-1)=(2x+2)(x-1)=2(x+1)(x-1)=2(x²-1)
vậy 2x²-4x+2=2(x²-1)
b)x²+5x=0
⇔x(x+5)=0
⇔\(\left[ \begin{array}{l}x=0\\x+5=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=0\\x=-5\end{array} \right.\)
vậy x=0 hoặc x=-5