a, $\sqrt{\frac{36}{7-4\sqrt{3}}}$ + $\sqrt{7-4\sqrt{3}}$ - $\sqrt{75}$
b, ($\frac{\sqrt{14}-\sqrt{7}}{1-\sqrt{2}}$ + $\frac{\sqrt{15}-\sqrt{5}}{1-\sqrt{3}}$ ) : $\frac{1}{\sqrt{7}-\sqrt{5}}$
c, ($\frac{2\sqrt{3}-\sqrt{6}}{\sqrt{8}-2}$ - $\frac{\sqrt{216}}{3}$) . $\frac{1}{\sqrt{6}}$
d, $\frac{\sqrt{2}+\sqrt{3}+\sqrt{10}+\sqrt{15}}{1+\sqrt{5}}$
(giúp mình với, hứa vote 5*)