Em tham khảo nha:
\(\begin{array}{l}
a)\\
R + 2HCl \to RC{l_2} + {H_2}\\
{n_{{H_2}}} = \dfrac{{3,36}}{{22,4}} = 0,15\,mol\\
{n_R} = {n_{{H_2}}} = 0,15\,mol\\
{M_R} = \dfrac{{3,6}}{{0,15}} = 24\,g/mol \Rightarrow R:Magie(Mg)\\
{n_{HCl}} = 2{n_{{H_2}}} = 0,3\,mol\\
m = {m_{{\rm{dd}}HCl}} = \dfrac{{0,3 \times 36,5}}{{14,6\% }} = 75g\\
{m_{{\rm{dd}}spu}} = 3,6 + 75 - 0,15 \times 2 = 78,3g\\
{n_{MgC{l_2}}} = {n_{{H_2}}} = 0,15\,mol\\
{C_\% }MgC{l_2} = \dfrac{{0,15 \times 95}}{{78,3}} \times 100\% = 18,2\% \\
b)\\
2R + 2nHCl \to 2RC{l_n} + n{H_2}\\
{n_{{H_2}}} = \dfrac{{4,48}}{{22,4}} = 0,2\,mol\\
{n_R} = \dfrac{{0,2 \times 2}}{n} = \dfrac{{0,4}}{n}\,mol\\
{M_R} = \dfrac{{11,2}}{{\frac{{0,4}}{n}}} = 28n\,g/mol\\
n = 2 \Rightarrow {M_R} = 56g/mol \Rightarrow R:Fe\\
{n_{HCl}} = 2{n_{{H_2}}} = 0,4\,mol\\
m = {m_{{\rm{dd}}HCl}} = \dfrac{{0,4 \times 36,5}}{{7,3\% }} \times 110\% = 220g\\
{m_{{\rm{dd}}spu}} = 11,2 + 220 - 0,2 \times 2 = 230,8g\\
{n_{FeC{l_2}}} = {n_{{H_2}}} = 0,2\,mol\\
{C_\% }FeC{l_2} = \dfrac{{0,2 \times 127}}{{230,8}} \times 100\% = 11\%
\end{array}\)
