Đáp án:
$A: C_2H_4$
$B: C_2H_6$
$C: CH_3-CH_2-CH_2-CH_3$
$H: C_2H_5Cl$
$I: C_2H_5OH$
$G: CH_2=CH-CH=CH_2$
$D: BrCH_2-CHBr-CH=CH_2$
$E: cis-BrCH_2-CH=CH-CH_2Br$
$F: trans-BrCH_2-CH=CH-CH_2Br$
PTHH:
$C_2H_4+H_2\xrightarrow{{Ni, t^o}} C_2H_6$
$C_2H_6\xrightarrow{{xt, t^o}} C_2H_4+H_2$
$C_2H_4+HCl\to C_2H_5Cl$
$C_2H_4+H_2O\xrightarrow{{H^+, t^o}} C_2H_5OH$
$CH_3-CH_2-CH_2-CH_3\xrightarrow{{xt, t^o}} C_2H_6+C_2H_4$
$CH_3-CH_2-CH_2-CH_3\xrightarrow{{xt, t^o}} C_2H_6+C_2H_4$
$C_2H_6+Cl_2\xrightarrow{{as}} C_2H_5Cl+HCl$
$C_2H_5Cl+NaOH\xrightarrow{{t^o}} C_2H_5OH+NaCl$
$C_2H_5OH+HCl\to C_2H_5Cl+H_2O$
$2C_2H_5OH\xrightarrow{{ZnO, Al_2O_3, t^o}} CH_2=CH-CH=CH_2+2H_2O+H_2$
$CH_3-CH_2-CH_2-CH_3\xrightarrow{{xt, t^o}} CH_2=CH-CH=CH_2+2H_2$
$CH_2=CH-CH=CH_2+2H_2\xrightarrow{{t^o, Ni}} CH_3-CH_2-CH_2-CH_3$
$CH_2=CH-CH=CH_2+Br_2\xrightarrow{{-80^oC}} CH_2Br-CHBr-CH=CH_2$
$CH_2=CH-CH=CH_2+Br_2\xrightarrow{{40^oC}} CH_2Br-CH=CH-CH_2Br$
