Đáp án:
`a,`
`x ÷ (-3/4)^2 = -3/4`
`-> x = -3/4 × (-3/4)^2`
`-> x = (-3/4)^3`
`-> x = (-27)/64`
Vậy `x= (-27)/64`
`b,`
`(4/7)^4 × x = (4/7)^6`
`-> x= (4/7)^6 ÷ (4/7)^4`
`-> x = (4/7)^2`
`-> x = 16/49`
Vậy `x = 16/49`
`c,`
`(1/2)^2 × x = (1/2)^5`
`-> x = (1/2)^5 ÷ (1/2)^2`
`-> x = (1/2)^3`
`-> x = 1/8`
Vậy `x = 1/8`
`d,`
`(-1/3)^3 × x = 1/81`
`-> (-1/3)^3 × x = (1/3)^4`
`-> x = (1/3)^4 × (-1/3)^3`
`-> x = -1/3`
Vậy `x= -1/3`
`e,`
`(-32)/(-2^x)= 4`
`-> -32 = -2x^2 × 4`
`-> -2x^2= -32 ÷ 4`
`-> -2x^2= -8`
`-> x^2=-8 ÷ (-2)`
`-> x^2 =4`
`->` \(\left[ \begin{array}{l}x^2=2^2\\x^2=(-2)^2\end{array} \right.\)
`->` \(\left[ \begin{array}{l}x=2\\x=-2\end{array} \right.\)
Vậy `x=2` hoặc `x=-2`
`f,`
`8/2^x=2`
`-> 8 = 2^x × 2`
`->2^x = 8 ÷ 2`
`-> 2^x = 4`
`-> 2^x = 2^2`
`-> x = 2`
Vậy `x=2`
`g,`
`(1/2)^{2n - 1} = 1/8`
`-> (1/2)^{2n - 1} = (1/2)^3`
`-> 2n - 1 = 3`
`-> 2n =3 + 1`
`-> 2n = 4`
`-> n = 4 ÷ 2`
`-> n = 2`
Vậy `n = 2`
