Em tham khảo nha :
\(\begin{array}{l}
a)\\
{C_6}{H_{12}}{O_6} \to 2{C_2}{H_5}OH + 2C{O_2}\\
{n_{C{O_2}}} = \frac{{22,4}}{{22,4}} = 1mol\\
{n_{{C_2}{H_5}OH}} = {n_{C{O_2}}} = 1mol\\
{m_{{C_2}{H_5}OH}} = 1 \times 46 = 46g\\
b)\\
{n_{{C_6}{H_{12}}{O_6}}} = \dfrac{{{n_{C{O_2}}}}}{2} = 0,5mol\\
{m_{{C_6}{H_{12}}{O_6}}} = 0,5 \times 180 = 90g\\
\text{Khối lượng glucozo cần dùng là :}\\
{m_{{C_6}{H_{12}}{O_6}}} = \dfrac{{90 \times 100}}{{90}} = 100g
\end{array}\)