Đáp án:
a) (2x+3)^2 - 3(x-4) (x+4) = (x-2)^2
=4x^2+12+9-3 (x^2 -16)=x^2-4x+4+1
=4x^2+12x+9-3x^2+48=x^2-4x+5
=x^2 +12x+57=x^2-4x+5
=12x+57=-4x+5
=12x+4x=5-57
=16x=-52
=x=-13/4
c) x(x-1)-(x-3)(x-4)=5
=x^2-x - (x^2+4x-3x-12)= 5
=X^2-x-(x^2+x-12)=5
=x^2-x-x^2+12=5
-2x+12=5
=-2x=5-12
=-2=-7
=2/7
d) (2x+1)(2x-1)=4x(x-7)-3x
4x^2-1=4x^2-28-3x
-1=-28x-3x
-1=-31x
x=1/31