Giải thích các bước giải:
Bài 1: a/ $(x+4)^2$
$=x^2+2.4x+4^2$
$=x^2+8x+16$
b/ $(2x-5)^2$
$=(2x)^2-2.5.2x+5^2$
$=4x^2-20x+25$
c/ $(\dfrac{1}{2}x-1)^2$
$=(\dfrac{1}{2}x)^2-2.\dfrac{1}{2}x+1$
$=\dfrac{1}{4}x^2-x+1$
d/ $(3x+2y)^2$
$=(3x)^2+2.3x.2y+(2y)^2$
$=9x^2+12xy+4y^2$
e/ $(2x^2y-3xy^2)^2$
$=(2x^2y)^2-2.2x^2y.3xy^2+(3xy^2)^2$
$=4x^4y^2-12x^3y^3+9x^2y^4$
f/ $(x+\dfrac{1}{3}y)^2$
$=x^2+2.x.\dfrac{1}{3}y+(\dfrac{1}{3}y)^2$
$=x^2+\dfrac{2}{3}xy+\dfrac{1}{9}y^2$
Bài 2: a/ $A=x^2-6x+25=x^2-2.3x+3^2+16=(x-3)^2+16$
b/ $B=9x^2+12x-1=(3x)^2+2.3x.2+2^2-5=(3x+2)^2+(-5)$
c/ $C=3x^2-12x+5=3x^2-12x+12-7=3(x^2-4x+4)-7=3(x-2)^2+(-7)$
Chúc bạn học tốt !!!