$2/$
$|2x - 2| - 3x + 1 = -2$
$⇔|2x-2|=-2-1+3x$
$⇔|2x-2|=-3+3x$
$⇔$\(\left[ \begin{array}{l}2x-2=-3+3x\\2x-1=3-3x\end{array} \right.\)
$⇔$\(\left[ \begin{array}{l}x=1\\x=4/5\end{array} \right.\)
$3/$
$\frac{n+1}{n-5}=\frac{n-5+6}{n-5}=1+\frac{6}{n-5}$
để $n+1$ là bội của $n-5$
$⇔n-5∈Ư(6)={±1;±2;±3;±6}$
$+)n-5=1⇔n=6$
$+)n-5=-1⇔n=4$
$+)n-5=2⇔n=7$
$+)n-5=-2⇔n=3$
$+)n-5=3⇔n=8$
$+)n-5=-3⇔n=2$
$+)n-5=6⇔n=11$
$+)n-5=-6⇔n=-1$