Bài 1:
Ta có: 2x-1 lẻ => \(\left[ \begin{array}{l}|2x-1|=1\\|2x-1|=3\end{array} \right.\)
TH1: \(\left[ \begin{array}{l}2x-1=1\\2x-1=-1\end{array} \right.\)
=> \(\left[ \begin{array}{l}2x=2\\2x=0\end{array} \right.\)
=> \(\left[ \begin{array}{l}x=1\\x=0\end{array} \right.\)
TH2: \(\left[ \begin{array}{l}2x-1=3\\2x-1=-3\end{array} \right.\)
=> \(\left[ \begin{array}{l}2x=4\\2x=-2\end{array} \right.\)
=> \(\left[ \begin{array}{l}x=2\\x=-1\end{array} \right.\)
Vậy x ∈ {-1;0;1;2}
Bài 2:
|x+1| ≤ 2 => \(\left[ \begin{array}{l}|x+1|=2\\|x+1|=1\\|x+1|=0\end{array} \right.\)
=> \(\left[ \begin{array}{l}x+1=2\\x+1=-2\\x+1=1\\x+1=-1\\x+1=0\end{array} \right.\)
=> \(\left[ \begin{array}{l}x=1\\x=-3\\x=0\\x=-2\\x=-1\end{array} \right.\) (T/M)
CHúc bạn học tốt)
