Bài 2:
a. $n_{Zn}=\dfrac{6,5}{65}=0,1(mol)$
$Zn+2HCl\to ZnCl_2+H_2$
$b.$ $n_{H_2}=n_{Zn}=0,1(mol)$
$\to V_{H_2}=0,1.22,4=2,24(l)$
b. $n_{ZnCl_2}=n_{Zn}=0,1(mol)$
$\to m_{ZnCl_2}=0,1.136=13,6(g)$
Bài 3:
$a)$
$n_{Al}=\dfrac{5,4}{27}=0,2(mol)$
$2Al+6HCl\to 2AlCl_3+3H_2$
$b)$
$n_{H_2}=\dfrac 32.n_{Al}=0,3(mol)$
$\to V_{H_2}=0,3.22,4=6,72(l)$
$n_{AlCl_3}=n_{Al}=0,2(mol)$
$\to m_{AlCl_3}=0,2.133,5=26,7(g)$
Bài 4:
$K_2O:kali\; oxit$
$SO_2: sunfuro$
$Fe_2O_3:$ sắt ( III ) oxit
$P_2O_5: diphotpho\; pentaoxit$
$CuO:$ đồng ( II ) oxit
$CO_2: cacbon\; dioxit$