`text( ta có : )y=f(x)=-3/2x+5/2`
`f (0)= -3/2*0+ 5/2=5/2`
`f (1)= -3/2*1+ 5/2=1`
`f (-1)= -3/2*(-1)+ 5/2=4`
`f (3)= -3/2*3+ 5/2=-2`
`f(-3)=-3/2*(-3)+5/2=7`
`f(1/4)=-3/2*1/4+5/2=-17/8`
`f(-1/2)=-3/2*(-1/2)+5/2=13/4`
` f (3/5)= -3/2*3/5+ 5/2=-8/5`
` f (-3/2)= -3/2*(-3/2)+ 5/2=19/4`