Bài 5:
$\frac{m+1}{x-1}=m-1$
⇔ $\frac{m+1-(m-1)(x-1)}{x-1}=0$
⇔$2m-mx+x=0$
⇔$m(2-x)=-x$
Nếu 2-x=0⇒x=2⇒0m=-2 (loại)
Chia 2 vế cho 2-x$\neq$0
⇒$m=\frac{-x}{2-x}=$ $\frac{2-x-2}{2-x}=1-$ $\frac{2}{2-x}$
⇒2-x∈Ư(2)={±1;±2}
2-x=1⇒x=1⇒m=-1
2-x=-1⇒x=3⇒m=3
2-x=2⇒x=0⇒m=0
2-x=-2⇒x=4⇒m=2
Vậy m∈{-1;3;0;2}