Bài 4:
ΔAOB cân (OA = OB) $⇒\widehat{OAB}=\widehat{B}$
Lại có: OB = OC (gt) ⇒ OA = OC
⇒ ΔOAC cân tại O $⇒\widehat{OAC}=\widehat{C}$
ΔABC có: $\widehat{BAC}+\widehat{B}+\widehat{C}=180^{o}$
$⇒\widehat{OAC}+\widehat{OAB}+\widehat{B}+\widehat{C}=180^{o}$
$⇒ 2(\widehat{OAC}+\widehat{OAB})=180^{o}$
$⇒\widehat{OAC}+\widehat{OAB}=90^{o}$
$⇒\widehat{BAC}=90^{o}$