Đáp án:
$Cu_2O$
Giải thích các bước giải:
\(\begin{array}{l}
CuO:\% {m_{Cu}} = \dfrac{{64}}{{64 + 16}} \times 100\% = 80\% \\
C{u_2}O:\% {m_{Cu}} = \dfrac{{64 \times 2}}{{64 \times 2 + 16}} \times 100\% = 88,89\% \\
CuS{O_4}.5{H_2}O:\% {m_{Cu}} = \dfrac{{64}}{{64 + 32 + 16 \times 4 + 5 \times 18}} \times 100\% = 25,6\% \\
Cu{(OH)_2}:\% {m_{Cu}} = \dfrac{{64}}{{64 + 16 \times 2 + 1 \times 2}} \times 100\% = 65,31\% \\
CuC{l_2}:\% {m_{Cu}} = \dfrac{{64}}{{64 + 35,5 \times 2}} \times 100\% = 47,41\%
\end{array}\)
