Đáp án:
B5.
1.
a) 750ml=0,75l
$C_{M}$$_{(KCl)}$ = $\frac{n KCl}{V dd}$=$\frac{1}{0,75}$ = 1,33M
b) $n_{CuSO}$$_{4}$ = $\frac{m CuSO4}{M CuSO4}$ = $\frac{400}{160}$ =2,5(mol)
$C_{M}$$_{(CuSO}$$_{4)}$ = $\frac{n CuSO4}{V dd}$ = $\frac{2,5}{4}$ = 0,625M
2.
a) C%$_{dd KCl}$ = $\frac{m KCl}{m dd KCl}$. 100% = $\frac{20}{600}$ .100%= 3,33%
b) C%$_{dd K2SO4}$ = $\frac{m K2SO4}{m dd K2SO4}$. 100% = $\frac{75}{1500}$ .100%= 5%