Ta có: \(3^{21}=3\cdot3^{20}=3\cdot\left(3^2\right)^{10}=3\cdot9^{10}\)
\(2^{31}=2\cdot2^{30}=2\cdot\left(2^3\right)^{10}=2\cdot8^{10}\)
Ta thấy: \(2< 3;8^{10}< 9^{10}\)
\(\Rightarrow3\cdot9^{10}>2\cdot8^{10}\)
hay \(3^{21}>2^{31}\)
Vậy \(3^{21}>2^{31}\)