Đáp án:
↓↓
Giải thích các bước giải:
Bài 1:
`i)`
`512.(2-128)-128.(-512)`
`=512.(-126)-128.(-512)`
`=(-512).126-128.(-512)`
`=(-512).(126-128)`
`=(-512).(-2)`
`=1024`
`k)`
`26.(-125)-125.(-36)`
`=(-26).125-125.(-36)`
`=125.[(-26)-(-36)]`
`=125.10`
`=1250`
Bài 2:
`b)`
`-3.|x-1|=-27`
`|x-1|=(-27):(-3)`
`|x-1|=9`
`=>`\(\left[ \begin{array}{l}x-1=-9 \\x=-8\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x-1=9 \\x=10\end{array} \right.\)
Vậy `x∉{-8;10}`
`g)`
`5-(10-x)=7`
`10-x=5-7`
`10-x=-2`
`x=10-(-2)`
`x=12`
Vậy `x=12`
`j)`
`-7.|x|=-35`
`|x|=-35:(-7)`
`|x|=5`
`=>x∉{-5;5}`
Vậy `x∉{-5;5}.`