a,
$CH_3-C\equiv CH+H_2\buildrel{{Pd/PbCO_3, t^o}}\over\longrightarrow CH_3-CH=CH_2$
b,
$CH_3-C\equiv CH+2Br_2\to CH_3-CBr_2-CHBr_2$
c,
$CH_3-C\equiv CH+AgNO_3+NH_3\to CH_3-C\equiv CAg+NH_4NO_3$
d,
$CH_3-C\equiv CH+HCl\buildrel{{Hg^{2+}, t^o}}\over\longrightarrow CH_3-CCl=CH_2$ (spc)
$CH_3-C\equiv CH+HCl\buildrel{{Hg^{2+}, t^o}}\over\longrightarrow CH_3=CH-CHCl$ (spp)