h) 5$5^{(x-2)(2x+3)}$ =1=$5^{0}$
⇔(x-2)(2x+3)=0
⇔ \(\left[ \begin{array}{l}x-2=0\\2x+3=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=2\\x=-\frac{3}{2}\end{array} \right.\)
i) $3^{-2}$.$3^{4}$.$3^{x}$ =$3^{-2+4+x}$ =$3^{x+2}$ =$3^{7}$
⇔x+2 =7 ⇔x=5
j) ²$((-0,5)³)^{x}$=$\frac{1}{64}$
⇔ $(\frac{-1}{8})^{x}$=$(\frac{-1}{8})^{2}$ ⇔x=2