Biết $\displaystyle \cos \left( a-\frac{b}{2} \right)=\frac{1}{2}$ và$\displaystyle \sin \left( a-\frac{b}{2} \right)>0$;$\displaystyle \sin \left( \frac{a}{2}-b \right)=\frac{3}{5}$ và$\displaystyle \cos \left( \frac{a}{2}-b \right)>0$. Giá trị$\displaystyle \cos \left( a+b \right)$ bằng
A. $\displaystyle \frac{24\sqrt{3}-7}{50}.$ 
B. $\displaystyle \frac{7-24\sqrt{3}}{50}.$ 
C. $\displaystyle \frac{22\sqrt{3}-7}{50}.$ 
D. $\displaystyle \frac{7-22\sqrt{3}}{50}.$

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