Đáp án:
A: Na
B: NaOH
C:\(N{a_2}S{O_4}\)
D:\(N{a_2}S{O_4}\)
E:\(BaC{l_2}\)
F:\(Ba{(N{O_3})_2}\)
G:\({H_2}O\)
Giải thích các bước giải:
\(\begin{array}{l}
Na + {H_2}O \to NaOH + \dfrac{1}{2}{H_2}\\
2NaOH + {H_2}S{O_4} \to N{a_2}S{O_4} + 2{H_2}O\\
N{a_2}S{O_4} + BaC{l_2} \to 2NaCl + BaS{O_4}\\
2NaOH + {H_2}S{O_4} \to N{a_2}S{O_4} + 2{H_2}O\\
N{a_2}S{O_4} + Ba{(N{O_3})_2} \to 2NaN{O_3} + BaS{O_4}
\end{array}\)
