Đáp án:
$x=7, x=\frac{15}{4}$
Giải thích các bước giải:
$\frac{7-x}{2}+\frac{2}{3}(x-7)(x-3)=0\\
\Leftrightarrow -\frac{x-7}{2}+\frac{2}{3}(x-7)(x-3)=0\\
\Leftrightarrow (x-7)(\frac{-1}{2}+\frac{2(x-3)}{3})=0\\
\Leftrightarrow (x-7)(\frac{-3}{6}+\frac{4(x-3)}{6})=0\\
\Leftrightarrow (x-7)(\frac{-3}{6}+\frac{4(x-3)}{6})=0\\
\Leftrightarrow (x-7)\frac{-3+4x-12}{6}=0\\
\Leftrightarrow x-7=0,\frac{-3+4x-12}{6}=0\\
\Leftrightarrow x=7, 4x-15=0\\
\Leftrightarrow x=7, x=\frac{15}{4}$