Em tham khảo nha:
\(\begin{array}{l}
{M_{{C_8}{H_{10}}{O_2}{N_4}}} = 12 \times 8 + 10 + 16 \times 2 + 14 \times 4 = 194\,g/mol\\
\% {m_C} = \dfrac{{12 \times 8}}{{194}} \times 100\% = 49,48\% \\
\% {m_H} = \dfrac{{10}}{{194}} \times 100\% = 5,15\% \\
\% {m_O} = \dfrac{{16 \times 2}}{{194}} \times 100\% = 16,49\% \\
\% {m_N} = 100 - 49,48 - 5,15 - 16,49 = 28,88\%
\end{array}\)