1/
$a,PTPƯ:2Al+6HCl\xrightarrow{} 2AlCl_3+3H_2↑$
b, Đổi 200 ml = 0,2 lít.
$⇒n_{HCl}=0,2.0,3=0,06mol.$
$Theo$ $pt:$ $n_{Al}=\dfrac{1}{3}n_{HCl}=0,02mol.$
$⇒m_{Al}=0,02.27=0,54g.$
$Theo$ $pt:$ $n_{H_2}=\dfrac{1}{2}n_{HCl}=0,03mol.$
$⇒V_{H_2}=0,03.22,4=0,672l.$
2/
$a,PTPƯ:Zn+H_2SO_4\xrightarrow{} ZnSO_4+H_2↑$
$b,n_{H_2SO_4}=\dfrac{200.9,8\%}{98}=0,2mol.$
$Theo$ $pt:$ $n_{Zn}=n_{H_2}=n_{H_2SO_4}=0,2mol.$
$⇒m_{Zn}=0,2.65=13g.$
$⇒V_{H_2}=0,2.22,4=4,48l.$
chúc bạn học tốt!