Câu 1
4al + 3o2----> 2al2o3
0.2 0.15 0.1
n al=5.4/27=0.2(mol)
=) V o2 đktc=0.15*22.4=3.36(l)
Do Vo2 = 20%Vkk=) Vkk=5 Vo2=5*3.36=16.8(l)
b)
m al2o3=0.1*102=10.2(g)
Câu 2
2zn + o2-----> 2zno
0.3 0.15
V o2 = 16.8/5=3.36(l)
n o2 = 16.8/5/22.4=0.15(mol)
m zn=0.3*65=19.5(g)
Câu 3
4p + 5o2----> 2p2o5
0.4 0.5 0.2
n p2o5=28.5/142=0.2(mol)
V o2=0.5*22.4=11.2(l)
=) Vkk = 5Vo2= 5*11.2=56(l)
b)
m p = 0.4*31=12.4(g)