Em tham khảo nha:
\(\begin{array}{l}
1)\\
a)\\
{n_{C{O_2}}} = {n_{CaC{O_3}}} = \dfrac{{30}}{{100}} = 0,3\,mol\\
{n_{{H_2}O}} = \dfrac{{5,4}}{{18}} = 0,3\,mol\\
{n_C} = {n_{C{O_2}}} = 0,3\,mol\\
{n_H} = 2{n_{{H_2}O}} = 0,6\,mol\\
{n_C}:{n_H} = 0,3:0,6 = 1:2 \Rightarrow CTDGN:C{H_2}\\
{M_A} = 21 \times 2 = 42g/mol \Rightarrow 14n = 42 \Leftrightarrow n = 3\\
CTPT:{C_3}{H_6}\\
b)\\
m = {m_C} + {m_H} = 0,3 \times 12 + 0,6 = 4,2g\\
2)\\
{C_2}{H_4} + {H_2}O \xrightarrow{t^0,xt} {C_2}{H_5}OH\\
{C_2}{H_5}OH + {O_2} \xrightarrow{\text{ lên men }} C{H_3}COOH + {H_2}O\\
C{H_3}COOH + {C_2}{H_5}OH \xrightarrow{t^0,xt} C{H_3}COO{C_2}{H_5} + {H_2}O
\end{array}\)