Đáp án:
\(m = 4kg;F = 10N;\alpha = {30^0};\mu = 0,1\)
a> lực ma sat:
\({F_{m{\rm{s}}}} = \mu .m.g = 0,1.4.10 = 4N\)
b> gia tốc:
\(Fco{\rm{s}}\alpha - {F_{m{\rm{s}}}} = m.a = > a = \frac{{Fco{\rm{s}}\alpha - {F_{m{\rm{s}}}}}}{m} = \frac{{10.co{\rm{s30 - 4}}}}{4} = 1,17(m/{s^2})\)
c> t=10s
\(\left\{ \begin{array}{l}
v = a.t = 1,17.10 = 11,7m/s\\
S = \frac{{a.{t^2}}}{2} = \frac{{1,{{17.10}^2}}}{2} = 58,5m
\end{array} \right.\)