Xin chào,xin chào^^
$3$.$|x+9|.2=10$
$⇔ |x+9| = 5$
$⇔$ \(\left[ \begin{array}{l}x+9=5\\x+9=-5\end{array} \right.\)
$⇔$ \(\left[ \begin{array}{l}x=-4\\x=-14\end{array} \right.\)
Vậy $x$ ∈ {$-14;4$}
$4$, $3n+8$ $\vdots$ $n-1$
$⇔$ $3n+8-3(n-1)$ $\vdots$ $n-1$
$⇔$ $3n+8-3n+3$ $\vdots$ $n-1$
$⇔$ $11$ $\vdots$ $n-1$
$⇒$ $n-1$ ∈ Ư($11$)={$±1;±11$}
$⇔$ $n$ ∈ {$-10;0;2;12$}
Vậy $n$ ∈ {$-10;0;2;12$}