$a,PTPƯ:$
$Zn+2HCl\xrightarrow{} ZnCl_2+H_2↑$ $(1)$
$CuO+H_2\xrightarrow{t^o} Cu+H_2O$ $(2)$
b, Đổi 200 ml = 0,2 lít.
$⇒n_{HCl}=0,2mol.$
$Theo$ $pt1:$ $n_{Zn}=\dfrac{1}{2}n_{HC}=0,1mol.$
$⇒m_{Zn}=0,1.65=6,5g.$
$Theo$ $pt1:$ $n_{H_2}=\dfrac{1}{2}n_{HCl}=01mol.$
$c,Theo$ $pt2:$ $n_{Cu}=n_{H_2}=0,1mol.$
$⇒m_{Cu}=0,1.64=6,4g.$
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