Giải thích các bước giải:
$\sin{x}\cos{x} = \dfrac{1}{4}$
$\Leftrightarrow 2\sin{x}\cos{x} = \dfrac{1}{2}$
$\Leftrightarrow \sin{2x} = \dfrac{1}{2}$
$\Leftrightarrow \sin{2x} = \sin{\dfrac{\pi}{6}}$
$\Leftrightarrow \left[ \begin{array}{l}2x = \dfrac{\pi}{6} + k2\pi\\2x = \pi - \dfrac{\pi}{6} + k2\pi\end{array} \right.$
$\Leftrightarrow \left[ \begin{array}{l}x = \dfrac{\pi}{12} + k\pi\\2x = \dfrac{5\pi}{12} + k\pi\end{array} \right.$
