66/
$n_{SO_2}=67,2/22,4=3mol$
$S+2H_2SO_4\to 2H_2O+3SO_2↑$
$\text{Theo pt :}$
$n_S=1/3.n_{SO_2}=1/3.3=1mol$
$⇒m_S=1.32=32g$
67/
$n_{Zn}=6,5/65=0,1mol$
$Zn+H_2SO_4\to ZnSO_4+H_2↑$
$\text{Theo pt :}$
$n_{H_2SO_4}=n_{H_2}=n_{Zn}=0,1mol$
$⇒m_{H_2SO_4}=0,1.98=9,8g$
$V_{H_2}=0,1.22,4=2,24l$