Đáp án:
15. A
16. D
17. A
Giải thích các bước giải:
\(\begin{array}{l}
15.\\
Ba{(OH)_2} + C{O_2} \to BaC{O_3} + {H_2}O\\
{n_{C{O_2}}} = 0,1mol\\
\to {n_{BaC{O_3}}} = {n_{C{O_2}}} = 0,1mol \to {m_{BaC{O_3}}} = 19,7g\\
16.\\
CuO + 2HCl \to CuC{l_2} + {H_2}O\\
{n_{CuO}} = 0,1mol\\
\to {n_{CuC{l_2}}} = {n_{CuO}} = 0,1mol \to {m_{CuC{l_2}}} = 13,5g\\
17.\\
Fe + {H_2}S{O_4} \to FeS{O_4} + {H_2}\\
{n_{{H_2}}} = 0,3mol\\
\to {n_{Fe}} = {n_{{H_2}}} = 0,3mol \to {m_{Fe}} = 16,8g
\end{array}\)
