Giải thích các bước giải:
\(\begin{array}{l}
a,\\
1\frac{3}{4}x + 1\frac{1}{2} = \frac{{ - 5}}{4}\\
\Leftrightarrow \frac{7}{4}x + \frac{3}{2} = - \frac{5}{4}\\
\Leftrightarrow \frac{7}{4}x = - \frac{{11}}{4}\\
\Leftrightarrow x = - \frac{{11}}{7}\\
b,\\
\frac{1}{4} + \frac{3}{4}:x = \frac{2}{3}\\
\Leftrightarrow \frac{3}{4}:x = \frac{5}{{12}}\\
\Leftrightarrow x = \frac{3}{4}:\frac{5}{{12}}\\
\Leftrightarrow x = \frac{9}{5}\\
c,\\
5 - {\left( {1,3 - x} \right)^2} = 1\\
\Leftrightarrow {\left( {1,3 - x} \right)^2} = 4\\
\Leftrightarrow \left[ \begin{array}{l}
1,3 - x = 2\\
1,3 - x = - 2
\end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
x = - 0,7\\
x = 3,3
\end{array} \right.\\
d,\\
\left| {3x - 5} \right| - \frac{1}{7} = \frac{1}{3}\\
\Leftrightarrow \left| {3x - 5} \right| = \frac{{10}}{{21}}\\
\Leftrightarrow \left[ \begin{array}{l}
3x - 5 = \frac{{10}}{{21}}\\
3x - 5 = - \frac{{10}}{{21}}
\end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
x = \frac{{115}}{{63}}\\
x = \frac{{95}}{{63}}
\end{array} \right.
\end{array}\)
