Giải thích các bước giải:
a) Có `n_(Na_2CO_3)=(10,6)/106=0,1(mol)`
$PT:Na_2CO_3+H_2SO_4→Na_2SO_4+CO_2+H_2O\\\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }0,1\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }0,1\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }0,1\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }0,1\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }0,1\text{ }(mol)$
Theo PT: `n_(CO_2)=0,1mol`
`->V_(CO_2)=0,1xx22,4=2,24(l)`
b) Theo PT: `n_(Na_2SO_4)=0,1mol`
`->m_(Na_2SO_4)=0,1xx142=14,2(g)`
