Đáp án:
Ta có: $10^{2m}$ + $18^{}$
= $10^{2m}$ - $10^{m}$ + $10^{m}$ - $1^{}$ + $19^{}$
= ($10^{m}$.$10^{m}$ - $10^{m}$.$1^{}$) + ($10^{m}$ - $1^{}$) + $19^{}$
= $10^{m}$.($10^{m}$-1) + $10^{m}$ - $1^{}$ + $19^{}$
Ta có: $10^{m}$ - $1^{}$ ⋮ 19
nên $10^{m}$.($10^{m}$-1) ⋮ 19
19 ⋮ 19
Vậy $10^{2m}$ + $18^{}$ ⋮ 19
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